x^2+2y^2+3xy=28

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Solution for x^2+2y^2+3xy=28 equation: 


Simplifying
x2 + 2y2 + 3xy = 28

Reorder the terms:
3xy + x2 + 2y2 = 28

Solving
3xy + x2 + 2y2 = 28

Solving for variable 'x'.

Reorder the terms:
-28 + 3xy + x2 + 2y2 = 28 + -28

Combine like terms: 28 + -28 = 0
-28 + 3xy + x2 + 2y2 = 0

The solution to this equation could not be determined.

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